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2023 Mathematics Competition

Question 15

  • Mathematics
  • maths
  • competition
  • 2023

4 comments

Caleb Adeleye
1 year ago

COongrats Goodness Barak

Goodness Barak
1 year ago

EXPANDING .....
[(P^-8 Q⁴)/(5P^-2 Q⁴)] × [(P^6 /Q^-9)]
Q⁴ CAN NOW CANCEL EACH OTHER
[(1/5)(P^-8/P^-2)] × [P^6/Q^-9]
USING LAW OF INDICES I CAN NOW SUBTRACT THE POWERS
[(1/5)(P^-8--2)] × [P^6/Q^-9]
[(1/5)(P^-6)] × [P^6/Q^-9]
[(P^-6)/5] × (P^6/Q^-9)
MULTIPLYING....
[ P^-6 × P^6 ] /[5 ×Q^-9]
USING LAW OF INDICES I CAN NOW ADD THE POWERS
[P^-6+6]/[5Q^-9]
[P^O]/[5Q^-9]
ANYTHING RAISED TO POWER OF ZERO IS 1
1 /5Q^-9
(5Q^-9)^-1
(5^-1)(Q^-9×-1)
5^-1Q^9
(1/5) ×Q^9
(Q^9)/5.

Goodness Barak
1 year ago

EXPANDING .....
[(P^-8 Q⁴)/(5P^-2 Q⁴)] × [(P^6 /Q^-9)]
Q⁴ CAN NOW CANCEL EACH OTHER
[(1/5)(P^-8/P^-2)] × [P^6/Q^-8]
USING LAW OF INDICES I CAN NOW SUBTRACT THE POWERS
[(1/5)(P^-8--2)] × [P^6/Q^-9]
[(1/5)(P^-6)] × [P^6/Q^-9]
[(P^-6)/5] × (P^6/Q^-9)
MULTIPLYING....
[ P^-6 × P^6 ] /[5 ×Q^-9]
USING LAW OF INDICES I CAN NOW ADD THE POWERS
[P^-6+6]/[5Q^-9]
[P^O]/[5Q^-9]
ANYTHING RAISED TO POWER OF ZERO IS 1
1 /5Q^-9
(5Q^-9)^-1
(5^-1)(Q^-9×-1)
5^-1Q^9
(1/5) ×Q^9
(Q^9)/5.

Akinola Ajayi
1 year ago

(P-²Q³)³/5