2023 Mathematics Competition

Question 12

  • Mathematics
  • maths
  • 2023
  • competition

3 comments

X-5 =4√x
Divide both sides by 4
X-5/4 =√x
Find the square of both sides
X^2-10X+25/16 = x
Multiply both sides by 16
X^2 - 10x+25 = 16x
X^2-26x+25 = 0
Solve the quadratic equation
(X-1)(x-25) = 0
So therefore
X= 1
X = 25
Square of x are
X = 1
X = 625
2+X are
2+1= 3
2 +25 = 27
2+x- x^2 will be
2+1 -1= 2
2+25-625= -598

X-5 =4√x
Divide both sides by 4
X-5/4 =√x
Find the square of both sides
X^2-10X+25/16 = x
Multiply both sides by 16
X^2 - 10x+25 = 16x
X^2-26x+25 = 0
Solve the quadratic equation
(X-1)(x-25) = 0
So therefore
X= 1
X = 25
Square of x are
X = 1
X = 625
2+X are
2+1= 3
2 +25 = 27
2+x- x^2 will be
2+1 -1= 2
2+1-625= -622

Akinola Ajayi
1 year ago

=2 or -598